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objective Ques (310 results)
101)

If 3(sec2θ  + tan2θ) = 5, 0° < θ < 90°, then the value of cosec θ is:

SSC CHSL 2021
A)

\(\dfrac{1}{2}\)

B)

\(\dfrac{1}{\sqrt3}\)

C)

2

D)

\(\dfrac{2\sqrt3}{3}\)

102)

If 21 tan θ = 20, then(1 + sin θ - cos θ) : (1 - sin θ + cos θ) is equal to:

SSC CHSL 2021
A)

11 ∶ 13

B)

12 ∶ 11

C)

14 ∶ 15

D)

13 ∶ 15

103)

Simplify the following expression.
cos2 30° + cos2 40°+ cos2 50° + cos2 60°

SSC CHSL 2021
A)

2

B)

1

C)

\(\frac{5}{2}\)

D)

\(\frac{3}{2}\)

104)

If 5k = tanθ and \({5\over k}= sec\theta\), then what is the value of \(10\left(k^2-\frac{1}{k^2}\right) \) ?

SSC CHSL 2021
A)

\(\frac{2}{5}\)

B)

-2

C)

\(-\frac{2}{5}\)

D)

2

105)

If sin θ( 2 sin θ + 3) = 2, 0° < θ < 90°, then what is the value of (sec2 θ + cot2 θ - cos2 θ)?

SSC CHSL 2021
A)

\(\frac{43}{12}\)

B)

\(\frac{13}{3}\)

C)

\(\frac{31}{12}\)

D)

\(\frac{7}{2}\)

106)

If \(\sin θ=\frac{11}{15} \), then the value of (sec θ - tan θ) is:

SSC CHSL 2021
A)

\(\frac{\sqrt{26}}{13}\)

B)

\(\frac{1}{\sqrt{26}}\)

C)

\(\frac{4}{\sqrt{26}}\)

D)

\(\frac{2\sqrt{26}}{13}\)

107)

\(\frac{(1+\cos \theta)(cosec \theta-\cot \theta)\sec \theta}{\sin \theta(1-\sin\theta)(\sec \theta+\tan \theta)}=?\)

SSC CHSL 2021
A)

cos2 θ

B)

sin2 θ

C)

cosec2 θ

D)

sec2 θ

108)

If 3cos2θ - 4sinθ + 1 , 0° < θ < 90°, then the value of 3cos2θ + 5tan2θ will be:

SSC CHSL 2021
A)

\(5\frac{1}{5}\)

B)

\(5\frac{2}{3}\)

C)

\(5\frac{4}{5}\)

D)

\(6\frac{2}{3}\)

109)

If \(sin\theta={2\sqrt{ab}\over a+b}\), a > b > 0, then the value of \( \frac{cos\theta + 1}{cos \theta - 1}\) will be:

SSC CHSL 2021
A)

\(-\frac{b}{a}\)

B)

\(-\frac{a}{b}\)

C)

\(\frac{a}{b}\)

D)

\(\frac{b}{a}\)

110)

The value of \(\frac{3cos^227^\circ-5 + 3cos^263^\circ }{tan^232^\circ + 4 - cosec^2 58^\circ} \)\(+ sin35°cos55° \)\(+ cos35°sin55°\) is:

SSC CHSL 2021
A)

\(-\frac{1}{4}\)

B)

\(-\frac{1}{3}\)

C)

\(\frac{1}{3}\)

D)

\(1\frac{2}{3}\)

showing 101 - 110 results of 310 results

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