SSC CGL 20201)The value of 1800/20 x {(12-6) + (24-12)} is
1620
Follow BODMAS
SSC CGL 20192)The value of \({22.\bar{4}+11.5\bar{67}-33.5\bar{9}}\) is :
\({0.4\bar{12}}\)
\(22.\overline{4} + 11.5\overline{67} - 33.5\overline{9}\)
= 22.44444 + 11.56767 - 33.59999
= 22.44444 + 11.56767 - 33.59999
= 0.41212
=\( 0.4\overline{12}\)
SSC CGL 20193)The value of \(\left(2\frac{6}{7}of4\frac{1}{5}\div\frac{2}{3}\right)\times\)\(1\frac{1}{9}\div\)\(\left(\frac{3}{4}\times2\frac{2}{3}of\frac{1} {2}\div\frac{1}{4}\right)\) is :
5
\(\left(2\frac{6}{7}of4\frac{1}{5}\div\frac{2}{3}\right)\times1\frac{1}{9}\div\left(\frac{3}{4}\times2\frac{2}{3}of\frac{1}{2}\div\frac{1} {4}\right)\)
= \(\left(\frac{20}{7}of\frac{21}{5}\div\frac{2}{3}\right)\times\frac{10}{9}\div\left(\frac{3}{4}\times\frac{8}{3}of\frac{1}{2}\div\frac{1} {4}\right)\)
=\( \left(12\div\frac{2}{3}\right)\times\frac{10}{9}\div\left(\frac{3}{4}\times\frac{4}{3}\div\frac{1}{4}\right) = 18\times\frac{10}{9}\div\left(\frac{3}{4}\times\frac{16}{3}\right)\)
\(= 18\times\frac{10}{9}\div4 = 18\times\frac{10}{9}\times \frac{1}{4} = 5\)
SSC CGL 20194)The value of \(\sqrt{28+10\sqrt3}-\)\(\sqrt{7-4\sqrt3}\) is closest to :
6.5
\(\sqrt{28+10\sqrt3}-\sqrt{7-4\sqrt3}\) = \(\sqrt{(5)^2+(\sqrt3)^2+2\times5\sqrt3}-\sqrt{(2)^2+(\sqrt3)^2-2\times2\sqrt3}\) =\(\sqrt{(5+\sqrt3)^2}-\sqrt{(2-\sqrt3)^2}=6.464\)
SSC CGL 20195)The value of \(0.4\bar7+0.5\bar{03}-0.3\bar9\times0.\bar8\) is :
\(0.6\bar{25}\)
SSC CGL 20196)The value of \(24\times2\div12\)\(+12\div6\space of\space2\div\)\((15\div8\times4)\space of\)\(\space(28\div7\space of\space5)\) is :
\(4\frac{1}{6}\)
SSC CGL 20197)A student was asked to find the value of \(9\frac{4}{9}\div11\frac{1}{3}\space of\space\frac{1}{6}+\)\((1\frac{1}{3}\times1\frac{4}{5}\div\frac{3}{5})\)\(\times2\frac{1}{6}\space of\space \frac{2}{3}\)\(\div\frac{4}{3}\space of\space \frac{2}{3}\). His answer was \(19\frac{1}{4}\). What is the difference between his answer and the correct answer?
\(7\frac{3}{4}\)
SSC CGL 20198)The value of \((4.6)^4+(5.4)^4+(24.84)^2\over(4.6)^2+(5.4)^2+24.84\) is :
25.48
SSC CGL 20199)The value of \((1\frac{1}{3}\div2\frac{6}{7}\space of\space5\frac{3}{5})\div\)\((6\frac{2}{5}\div4\frac{1}{2}\space of\space5\frac{1}{3})\times\)\(({3\over4}\times2\frac{2}{3}\)\(\div{5\over9}\space of\space 1\frac{1}{5})\)\(=1+k,\) where k lies between :
-0.07 and -0.06
SSC CGL 201910)The expression \(\sqrt{10+2(\sqrt6-\sqrt{15}-\sqrt{10})}\) is equal to :
\(\sqrt3+\sqrt2-\sqrt5\)