SSC CPO 20201)If 4 – 2sin2 θ – 5cos θ = 0, 0° < θ < 90°, then the value of cos θ + tan θ is :
\(\dfrac{1+2\sqrt{3}}{2}\)
SSC CPO 20202)If 4(cosec2 57° - tan2 33°) - cos 90° - y tan2 66° tan2 24° =\(\dfrac{y}{2}\) , the value of y is:
\(\dfrac{8}{3}\)
SSC CPO 20203)The value of \(\frac {\sin^2 30^\circ + \cos^2 60^\circ - \sec 35^\circ.\sin 55^\circ}{\sec 60^\circ + \rm cosec\;30^\circ} \) is equal to:
\(-\frac 1 8\)
SSC CPO 20204)If sec3x = cosec(3x - 45°), where 3x is an acute angle, then x is equal to:
22.5°
SSC CPO 20205)The value of \(\frac{{{{\sin }^2}30^\circ + {{\cos }^2}60^\circ + sec45^\circ .sin45^\circ }}{{sec60^\circ + cosec30^\circ }} \) is:
\(\frac{3}{8}\)
SSC CPO 20206)If sin3x = cos(3x – 45°), 0° < 3x < 90°, then x is equal to:
22.5°
SSC CPO 20207)If 4θ is an acute angle, and cot 4θ = tan (θ - 5°) , then what is the value of θ?
19°
SSC CPO 20208)The value of \(\frac{{{{\sin }^2}{}52^\circ + 2 + {{\sin }^2}{{ }}38^\circ }}{{4{}{{\cos }^2}43^\circ - 5 + 4{{\cos }^2}{{}}47^\circ }}\) is:
- 3
SSC CPO 20209)If 4 - 2sin2θ - 5cosθ = 0, 0°< θ < 90°, then the value of cosθ - tanθ is:
\(\frac{{1 - 2\surd 3}}{2}\)
SSC CPO 202010)If 4(cosec2 57 - tan2 33) - cos 90 + y × tan2 66 × tan2 24 = y/2, then the value of y is:
-8