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SSC CHSL 2021 objective Ques (100 results)
11)

If \(\frac{4sin^2\theta + 5}{4sin^2\theta-1}\) , then the value of  is:

SSC CHSL 2021
A)

12

B)

3

C)

15

D)

9

12)

If \(0^0<\theta<90^0\), then \(\frac{{\left( {1 - \sin\theta } \right)\left( {\sec\theta + \tan\theta } \right)\tan\theta }}{{\left( {\tan\theta + \sec\theta + 1} \right)\left( {\cot\theta - \text{cosec} \ \theta + 1} \right)}} = ?\)

, Avg: 01:42 , 40%✓ SSC CHSL 2021
A)

(sin θ)/2 

B)

cos θ 

C)

sin θ  

D)

(cos θ)/2 

13)

If  \(tan A=\frac{{1.1}}{{6}}\) then what is the value of (4cos A - 7sin A)? Given that A is an acute angle.

, Avg: 01:30 , 50%✓ SSC CHSL 2021
A)

\(2\frac{{41}}{{61}}\)

B)

\(2\frac{{14}}{{61}}\)

C)

\(2\frac{{41}}{{71}}\)

D)

\(2\frac{{14}}{{71}}\)

14)

If  \(\rm \frac{3 \sqrt 3 \sec θ + 4 \tan θ}{3 \tan θ + \sqrt 3 \sec θ} = 2\),  0° < θ < 90°, then the value of cos θ will be:

, Avg: 01:05 , 50%✓ SSC CHSL 2021
A)

\(\frac{1}{2} \)

B)

\(\frac{\sqrt 3}{2}\)

C)

\(\frac{1}{4}\)

D)

\(\frac{1}{\sqrt 2}\)

15)

Solve the following equation.
2 cos2 θ + (4 + √3)sin θ - 2(1 + √3) = 0 where θ is an acute angle.

, Avg: 00:56 , 100%✓ SSC CHSL 2021
A)

30°

B)

45°

C)

15°

D)

60°

16)

What number should be subtracted from
4(sin460° + cos430°) - (tan245° - cot230°) + cos245° - cosec245°+ sec260° to get 2 ?

, Avg: 01:40 , 100%✓ SSC CHSL 2021
A)

5

B)

4

C)

7

D)

3

17)

If θ is an acute angle and sinθ = cosθ, then the value of 2 tan2θ + sin2θ - 1 is equal to:

, Avg: 00:18 , 25%✓ SSC CHSL 2021
A)

1

B)

-7

C)

3

D)

\(\rm \frac{3}{2}\)

18)

If A lies between 45° and 540°, and sin A = 0.5, what is the value of A/3 in degrees?

SSC CHSL 2021
A)

170°

B)

160°

C)

165°

D)

175°

19)

If \(cosθ = \rm \frac{2}{3}\) , then 2 sec2θ + 2 tanθ - 6 equals:

SSC CHSL 2021
A)

0

B)

2

C)

4

D)

1

20)

Solve for x?
sin2x - 4 sin x + 3 = 0, 0  ≤ x ≤  π/2

, Avg: 00:08 , 50%✓ SSC CHSL 2021
A)

π/6

B)

π/4

C)

π/2

D)

π/3

showing 11 - 20 results of 100 results